X^2+12x-1800=0

Solution for X^2+12x-1800=0 equation:

X^2+12X-1800=0

a = 1; b = 12; c = -1800;
Δ = b2-4ac
Δ = 122-4·1·(-1800)
Δ = 7344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7344}=\sqrt{144*51}=\sqrt{144}*\sqrt{51}=12\sqrt{51}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{51}}{2*1}=\frac{-12-12\sqrt{51}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{51}}{2*1}=\frac{-12+12\sqrt{51}}{2}
$